Python: How to print the local DNS Address ONLY?

Asked Aug 16 '19 at 13:09

Active Aug 16 '19 at 13:47

Viewed 420 times

when I type in nslookup in cmd I get this output:

Default Server: my server name.

Address: 192.168.2.1

I would like to use Python to output ONLY the DNS address. Just the number. How can I do that?

This is what I tried, but it opens up cmd again...

import os
print (os.system("nslookup"))

The output of print should be something like "192.168.2.1" ONLY.

asked Aug 16 '19 at 13:09

NoIdeaJoe

`os.system('ipconfig /all | findstr /R "DNS\ Servers')` is this what you are looking for? – Axois Aug 16 '19 at 13:13
Thank you. No, because that doesn't output the DNS. It just says 0. – NoIdeaJoe Aug 16 '19 at 13:17
Check this question:[enter link description here](https://stackoverflow.com/questions/166506/finding-local-ip-addresses-using-pythons-stdlib) – Grigoriy Gladkov Aug 16 '19 at 14:02
`print(os.system("hostname -I | cut -d' ' -f1"))` will get just the local ip - not sure how to suppress the extra line for the exit status of zero. – DaveStSomeWhere Aug 16 '19 at 14:23

0 Answers0