Why I am getting output 0 while running this code

Question

When I run this code, it gives 0 as output But I am calling func(a). Why it is not not assigning 1 to a

a = 0
def func(x):
    x = 1
func(a)
print(a)

I think you would find the answer to your question in this previous SO question https://stackoverflow.com/questions/986006/how-do-i-pass-a-variable-by-reference — pastaleg, Aug 18 '19 at 16:08

score 0 · Answer 1 · answered Aug 18 '19 at 16:12

0

This is because you are making a local variable in the function, ideally what you should be doing is this.

a = 0
def func():
    global a
    a = 1
func()
print(a)

answered Aug 18 '19 at 16:12

Satomatic

To avoid using a global: `def func(): return 1` then `a = func()`. – wjandrea Aug 18 '19 at 16:46

1 Answers1