How to convert javascript regex to php regex

Question

I want to convert this javascript regex to php regex. I have test the code can run.

<img.*?src='(?!http[s]*:\/\/img.[a-zA-Z0-9]*.test\/)(.*?)'

<img alt='' src='http://img.dev.teeeest/images/UID' />
<img alt='' src='https://img.deaaav.test.com/images/UID/' />
<img alt='' src='http://api.com/images/UID' />
<img alt='' src='http://img.deaSassav.test/images/UID' />
<img alt='' src='https://img.dev.test/images/UID' />

It will choose first three of these. I want php regex will have the same result.

$body = "<img alt='' src='http://img.dev.teeeest/images/UID' />
<img alt='' src='https://img.deaaav.test.com/images/UID.ux/' />
<img alt='' src='http://api.com/images/UID' />
<img alt='' src='http://img.deaSassav.test/images/UID' />
<img alt='' src='https://img.dev.test/images/UID' />";
$body = stripslashes($body);
$img_array = array();
preg_match_all('/<img[^>]*?src=[\'|\"](http[s]*:\/\/img.[a-zA-Z0-9]*.test\/[^"|^\']*?)[\'|\"][^>]*?>/isU', $body, $img_array);
$img_array = array_unique($img_array[1]);
echo "<pre>";
print_r($img_array);
echo "</pre>";

i use the website test https://regex101.com/ i attempt use add an ^ before http[s]. like this

<img[^>]*?src=[\'|\"](^http[s]*:\/\/img.[a-zA-Z0-9]*.test\/)[^"|^\']*?[\'|\"][^>]*?>

i want to negative what have this

http[s]*:\/\/img.[a-zA-Z0-9]*.test\/

i just don't know how to write it... i try a lot function. but do't have the same result — Night, Aug 19 '19 at 02:57
Can you include the functions you said you tried, but did not get the correct result with? — Spangle, Aug 19 '19 at 02:59
it is my first question on stackoverflow. maybe have some false expression sorry — Night, Aug 19 '19 at 02:59
It is clear to understand what you are wanting to do, however, it is hard to assist you if you do not include your attempts. — Spangle, Aug 19 '19 at 03:02
]*?src=[\'|\"](http[s]*:\/\/img.[a-zA-Z0-9]*.ux\/)[^"|^\']*?[\'|\"][^>]*?> this is my php regex. it can choose the last two. but i want the others — Night, Aug 19 '19 at 03:02
Always think about the problem thoroughly and constructively before posting. Do you think this kind of conversion is logical, possible or beneficial? — Udo E., Aug 19 '19 at 03:03
Please add the above to your question. Also include some more php, so we can run the code. — Spangle, Aug 19 '19 at 03:03
the php code can run. but can't get what i want result. i think just lack some expression. but don't know how to write — Night, Aug 19 '19 at 03:12

score 2 · Accepted Answer · answered Aug 19 '19 at 04:08

2

Your javascript regex works fine; you just need to change the s flag to m:

$body = "<img alt='' src='http://img.dev.teeeest/images/UID' />
<img alt='' src='https://img.deaaav.test.com/images/UID.ux/' />
<img alt='' src='http://api.com/images/UID' />
<img alt='' src='http://img.deaSassav.test/images/UID' />
<img alt='' src='https://img.dev.test/images/UID' />";
$body = stripslashes($body);
$img_array = array();
preg_match_all("/<img.*?src='(?!http[s]*:\/\/img.[a-zA-Z0-9]*.test\/)(.*?)/imU", $body, $img_array);
echo "<pre>";
print_r($img_array[0]);
echo "</pre>";

Output:

<pre>Array
(
    [0] => <img alt='' src='http://img.dev.teeeest/images/UID' />
    [1] => <img alt='' src='https://img.deaaav.test.com/images/UID.ux/' />
    [2] => <img alt='' src='http://api.com/images/UID' />
)
</pre>

Demo on 3v4l.org

answered Aug 19 '19 at 04:08

Nick

138,499
22
57
95

It doesn't work on php, but thank you for your answer. – Night Aug 19 '19 at 05:40
@Night i've given you a working demo in PHP. What do you mean, it doesn't work? – Nick Aug 19 '19 at 05:41
@Night if you want exactly the same output as the other answer, just change `$img_array[0]` to `$img_array[1]` https://3v4l.org/ppRKp – Nick Aug 19 '19 at 05:43
yes...i just try it. it is on $img_array[1] thank you – Night Aug 19 '19 at 05:49

Emma · Answer 2 · 2019-08-19T05:55:56.650

0

This expression might also work:

<img\b.*?\bsrc=['"](?!https?:\/\/img\.[a-z0-9]*\.test\/)([^'"]*)

If you wish to explore/simplify/modify the expression, it's been explained on the top right panel of regex101.com. If you'd like, you can also watch in this link, how it would match against some sample inputs.

edited Aug 19 '19 at 05:55

answered Aug 19 '19 at 04:17

Emma

27,428
11
44
69

How to convert javascript regex to php regex

2 Answers2