Why else condition executing two times in while loop in C

Question

"Else condition is executing two times and printing two times in while loop,if-else is not working properly,"

"I also tried the goto statement, I get the same problem"

#include<stdio.h>
#include<conio.h>
int main ()
{
  int count=0;
  char select;
  while(count==0)
  {
    printf("please select options\n");
    scanf("%c", &select);
    if (select=='b' || select=='B')
    {
        printf("you have selected b");
        count=1;
    }
    else
    {
      printf("why this line printing two time\n");
    }
  }
 return 0;
}

result

please select options
g
why this line printing two time
please select options
why this line printing two time
please select options

"When I take input other than 'b'/'B', I expect out to print the else condition and again run while loop, but the actual output is printing else condition two times"a result of my code

When you enter any char you press also key. Your loop receives 2 inputs: the wrong char and the enter code. That's why it runs twice. — Frankie_C, Aug 20 '19 at 08:53

score 3 · Accepted Answer · answered Aug 20 '19 at 08:55

3

When you use scanf to get a character you should use

scanf(" %c, &c);

Instead of

scanf("%c, &c);

Leaving a blank space tells to scanf to skip optional white space.

answered Aug 20 '19 at 08:55

LucasFab

95
10

"would you like to share more about "space" in scanf" – iamaksingh11 Aug 20 '19 at 09:23

Why else condition executing two times in while loop in C

1 Answers1