How to get SyntaxNode "MethodDeclarationSyntax" from Semantic "Method"?

Question

Syntax model and Semantic model communication

I have an "InvocationExpressionSyntax" "invocation" , from which i want to access "MethodDeclarationSyntax".

Don't want just to compare their names, because the method parameters may differ.

By using semantic model I got access to Operation of invocation. By operation I have an access to TargetMethod. I would like to get MethodDeclarationSyntax of that method.

var operation = (IInvocationOperation) semanticModel.GetOperation(invocation);
var methodInvoked = operation.TargetMethod;

Do you really want the declaration syntax? Or do you want know the parameters? — Paulo Morgado, Aug 20 '19 at 16:52
I needed to know the declaration syntax to examine method body — Martin Cehelský, Aug 21 '19 at 07:23

Abedron · Accepted Answer · 2019-08-21T09:43:58.800

1

You can use this method

private static SyntaxNode GetDeclarationSyntaxNode(InvocationExpressionSyntax invocationSyntax, SemanticModel semanticModel)
{
    var methodSymbol = (IMethodSymbol) semanticModel.GetSymbolInfo(invocationSyntax).Symbol;
    var syntaxReference = methodSymbol.DeclaringSyntaxReferences.FirstOrDefault();

    return syntaxReference?.GetSyntax();
}

There is detailed explanation Roslyn Get Method Declaration from InvocationExpression

Edit: include null-conditional operator to code

edited Aug 21 '19 at 09:43

answered Aug 21 '19 at 05:59

Abedron

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great, it's just what i needed. I apologize for a duplicate – Martin Cehelský Aug 21 '19 at 07:22
Your code expects that `methodSymbol.DeclaringSyntaxReferences` might be empty and the invokes `syntaxReference` without accounting for it. – Paulo Morgado Aug 21 '19 at 09:15
Thanks, I wrote null-conditonal operator to example code – Abedron Aug 21 '19 at 09:45

How to get SyntaxNode "MethodDeclarationSyntax" from Semantic "Method"?

Syntax model and Semantic model communication

1 Answers1