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how can I sort a dictionary in ascending order of values?

I have something like this :

["user1": 3764, "user5": 23, "user87": 875, "user21": 54987, ... ]

And I would like to get a dictionary ranked in ascending order of its values, like this : 

["user5": 23, "user87": 875, "user1": 3764, "user21": 54987, ...]
Leo Dabus
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Thomas
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    As has been discussed here countless times, dictionaries have no order. – rmaddy Aug 20 '19 at 17:02
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    Dictionaries guarantee no order (in memory), but there are applications where an ordered dict is useful. Depending on your final goal, you could take a look a `OrderedDict` or write a `class` around `dict` that gives you ordered output in the way you want it. – Sergio Pulgarin Aug 20 '19 at 17:14

1 Answers1

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Try this.

let userRankDict = ["user1": 3764, "user5": 23, "user87": 875, "user21": 54987]
let sortedUserRankDict = userRankDict.sorted{ $0.value < $1.value }
print(sortedUserRankDict)

Sorted userRankDict:

[(key: "user5", value: 23), (key: "user87", value: 875), (key: "user1", value: 3764), (key: "user21", value: 54987)]

Vinu Jacob
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