How to exit from nested for loop using break statement in Python

Question

[tmp.py]

#is_skip = False             # Alt. approach
for i in range(5):
    for j in range(3):
        if j == 2:
#            is_skip = True  # Alt. approach
            break
        print('I, J => ', i, j)
#    if is_skip:             # Alt. approach
#        break               # Alt. approach

[Expected]

I, J =>  0 0
I, J =>  0 1

[Current]

I, J =>  0 0
I, J =>  0 1
I, J =>  1 0
I, J =>  1 1
I, J =>  2 0
I, J =>  2 1
I, J =>  3 0
I, J =>  3 1
I, J =>  4 0
I, J =>  4 1

Any other best approach is available, except the above commented one.

Thanks,

Use `range(2)` instead of `range(5)`. Sorry, but your example is so contrived that it becomes unclear... — Ulrich Eckhardt, Aug 22 '19 at 06:46
@Guy `if j == 2: return None` => compile error `SyntaxError: 'return' outside function` — Jai K, Aug 22 '19 at 06:46
Of course, when we say `return` you should put that in a function. Shouldn't that go without saying? — trincot, Aug 22 '19 at 06:47
@JaiK Just `return`, without `None`. All the code should be in a function. — Guy, Aug 22 '19 at 06:47

score 0 · Answer 1 · answered Aug 22 '19 at 06:50

0

make a function and then return from that when condition matches:

def loopBreakExample():
    for i in range(5):
        for j in range(3):
            if j == 2:

                return
            print('I, J => ', i, j)
loopBreakExample()

answered Aug 22 '19 at 06:50

SM Abu Taher Asif

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How to exit from nested for loop using break statement in Python

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