Assign awk output to variable

Question

I'm trying to assign the output of awk to variable. I tried with solutions specified here but nothing seems to work. I'm first doing curl and then parsing the result from there

#!/bin/sh 

KEY="title"

curl https://jsonplaceholder.typicode.com/todos/1 | statu=$(awk -F'[,:}]' 
'{for(i=1;i<=NF;i++){if($i~/'$KEY'\042/){print $(i+1)}}}'  | tr -d '"')

echo "This is status" "$statu"

curl should be inside the $(...) as well – lw0v0wl Aug 23 '19 at 07:23 — lw0v0wl, Aug 23 '19 at 07:23

score 0 · Accepted Answer · answered Aug 23 '19 at 07:23

0

You should use command substitution like follows:

#!/bin/sh 

KEY="title"

statu=$(curl https://jsonplaceholder.typicode.com/todos/1 | awk -F'[,:}]' 
'{for(i=1;i<=NF;i++){if($i~/'$KEY'\042/){print $(i+1)}}}'  | tr -d '"')

echo "This is status" "$statu"

answered Aug 23 '19 at 07:23

mik1904

1,335
9
18

1

Awk can remove a double quote just fine; simply replace the `tr -d '"'` with something like `sub(/\042/, "", $(i+1))` inside the Awk script before printing. – tripleee Aug 23 '19 at 07:26
Oh yeah, i used the substitution in wrong place. Thank you very much! – Joonas Venäläinen Aug 23 '19 at 07:27

Assign awk output to variable

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