Delay javascript code before executing the next line

Question

I have a situation whereby i need to delay/stall the code a little before the next line of code will be executed.

    elementslist1[Math.floor(Math.random() * 11)].click()
    elementslist2[Math.floor(Math.random() * 11)].click();
    elementslist3[Math.floor(Math.random() * 11)].click();
    elementslist4[Math.floor(Math.random() * 11)].click();
    elementslist5[Math.floor(Math.random() * 11)].click();
    elementslist6[Math.floor(Math.random() * 11)].click();
    elementslist7[Math.floor(Math.random() * 11)].click();
    elementslist8[Math.floor(Math.random() * 11)].click();

    var input = document.getElementById('inputelement');

I need the code to delay for sometime after elementslist8[Math.floor(Math.random() * 11)].click(); has executed.Then after this delay it can now proceed to the next line which is

var input = document.getElementById('inputElement');

score 0 · Answer 1 · answered Aug 23 '19 at 21:21

0

So use a queue with a timeout

var elems = [elementslist1, elementslist2, elementslist3, elementslist4]

function clickNext() {
  // grab first item from queue
  elems.shift()[Math.floor(Math.random() * 11)].click()
  // if array still has items
  if (elems.length) {
    window.setTimeout(clickNext, 2000)
  }
}

// start it
clickNext();

answered Aug 23 '19 at 21:21

epascarello

204,599
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,there is still no delay between elementslist8 and the following line. – Ivaka Zakuri Aug 23 '19 at 22:18
Well you need to put the logic in there.... After the i`if (elems.length) { } else { /*logic here */ }` – epascarello Aug 23 '19 at 22:24
i cannot understand. – Ivaka Zakuri Aug 23 '19 at 22:38

score 0 · Answer 2 · answered Aug 23 '19 at 21:22

0

That's not possible in JavaScript.

You can use setTimeout though, it will be more complex than what you're asking though.

answered Aug 23 '19 at 21:22

FaZe Unempl0yedd

129
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UnemplOyedd,how complex? – Ivaka Zakuri Aug 23 '19 at 22:19
Annoyingly complex. – FaZe Unempl0yedd Aug 23 '19 at 22:57

Delay javascript code before executing the next line

2 Answers2