How to open the second link in the adjacent tab?

Question

I have been trying many functions to open a link in a tab I recently opened but it does not work.

Minimum reproducible example with commentary saying what happens after each line (this is using Selenium webdriver, Java):

driver.get("https://twitter.com") //opens twitter in tab 1(intended)

((JavascriptExecutor)driver).executeScript("window.open('https://google.com')"); //opens new tab (tab 2) then opens google.com(intended)
((JavascriptExecutor)driver).executeScript("window.location.replace('https://facebook.com')"); //opens facebook.com in tab 1 (unintended)

I want Facebook to open in tab 2 instead.

Answer 1

Once you open https://twitter.com as the base url and then open https://google.com in the adjascent tab. Next open the url https://facebook.com in the same adjascent tab you you have to induce WebDriverWait for numberOfWindowsToBe(2) and you can use the following solution:

• Code Block:

  public class A_demo 
  {
      public static void main(String[] args) throws Exception 
      {
          System.setProperty("webdriver.chrome.driver", "C:\\Utility\\BrowserDrivers\\chromedriver.exe");
          ChromeOptions options = new ChromeOptions();
          options.addArguments("start-maximized");
          options.setExperimentalOption("excludeSwitches", Collections.singletonList("enable-automation"));
          options.setExperimentalOption("useAutomationExtension", false);
          WebDriver driver = new ChromeDriver(options);
          driver.get("https://twitter.com");
          String parent_window = driver.getWindowHandle();
          ((JavascriptExecutor) driver).executeScript("window.open('https://google.com');");
          new WebDriverWait(driver,5).until(ExpectedConditions.numberOfWindowsToBe(2));
          Set<String> allWindows = driver.getWindowHandles();
          for(String child_window:allWindows)
              if(!parent_window.equalsIgnoreCase(child_window))
                  driver.switchTo().window(child_window);
          driver.get("https://facebook.com");
          driver.quit();
      }
  }