I'm using a script that calls awk with -i inplace extension inside a web app (on Debian 9). When deploying the app on the real server (centOS 7) it fails cause awk/gawk does not recognize the -i inplace input.
Example:
example.txt
one 1
two 2
three 3
when trying:
awk -i inplace -F'\t' '{if ($1 == "two") print "four","4"; else print $0}' example.txt
output error:
Usage: gawk [POSIX or GNU style options] -f progfile [--] file ...
Usage: gawk [POSIX or GNU style options] [--] 'program' file ...
POSIX options: GNU long options: (standard)
-f progfile --file=progfile
-F fs --field-separator=fs
-v var=val --assign=var=val
Short options: GNU long options: (extensions)
-b --characters-as-bytes
-c --traditional
-C --copyright
-d[file] --dump-variables[=file]
-e 'program-text' --source='program-text'
-E file --exec=file
-g --gen-pot
-h --help
-L [fatal] --lint[=fatal]
-n --non-decimal-data
-N --use-lc-numeric
-O --optimize
-p[file] --profile[=file]
-P --posix
-r --re-interval
-S --sandbox
-t --lint-old
-V --version
To report bugs, see node `Bugs' in `gawk.info', which is
section `Reporting Problems and Bugs' in the printed version.
gawk is a pattern scanning and processing language.
By default it reads standard input and writes standard output.
Examples:
gawk '{ sum += $1 }; END { print sum }' file
gawk -F: '{ print $1 }' /etc/passwd
I really need the awk script to work through inplace, I searched around and the web but found no clear solution, does anybody got a clue on how make it work?
Thanks a lot in advance for any help
