return single array from json by passing a value

Question

I have a json that I need to filter a specific key and value from

the following json

{
"5": {
      "Owner": "94EAC",
      "Record":"0121ln"
},
"15": {
      "Owner": "009AC",
      "Record":"0120Pc"
},
"1": {
      "Owner": "00G11A",
      "Record":"000lPcn"
},
"199": {
      "Owner": "00G1y9",
      "Record":"01211cn"
},
"33": {
      "Owner": "001AC",
      "Record":"0121n"
}

}

I would like to be able to pass the first int and get back array for that number. For example if I pass 15 I get

 {
      "Owner": "009AC",
      "Record":"0120Pc"
}

I tried foreach loop but cannot set specific value for the first int

If I assign $data = json

then $date[15] didn't work $data->15 also didn't work

I did also use the json decode and was able to print an array but wasn't able to get a single value Any help would be great, I did spend all day and still cannot get an answer. Thank you

Did "didn't work" materialize as an error message? – mario Aug 30 '19 at 23:07 — mario, Aug 30 '19 at 23:07

Dark Knight · Accepted Answer · 2019-08-30T23:17:00.410

0

Using Array:
$arr = json_decode($json, true);
print_r( $arr['15']);

Using Object:
$obj = json_decode($json);
print_r( $obj['15']);

Reference: json_decode

edited Aug 30 '19 at 23:17

answered Aug 30 '19 at 23:10

Dark Knight

6,116
1
15
37

Thank you so much, I was missing the '' I was passing the number without the '' – Ammar Aug 30 '19 at 23:19
Just remember if you are accessing a variable index, prefer to use square brackets. :) – Dark Knight Aug 30 '19 at 23:21

return single array from json by passing a value

1 Answers1