Given task is:
Enter 10 characters. For each character entered the corresponding function prints whether it is a digit 0-9 or not.(Also I use older compiler if anyone concerns about my "gets()" and goal is to do this without pointers.)
So far I tried something like this, but for some reason it does not work:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main(void){
char character[10][1];
char zero ='0';
char nine ='9';
int i;
printf("Enter 10 characters:\n");
for(i=0;i<10;i++){
gets(character[i]);
}
for(i=0;i<10;i++){
if(strcmp(character[i],zero)>=0 && strcmp(character[i],nine)<=0){
printf("%d. character '%c' is a digit.", i, character[i]);
}
else{
printf("%d. character '%c' is not a digit.", i, character[i]);
}
putchar('\n');
}
return 0;
}
Also I tried this, but it can not output correctly characters:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main(void){
char character[10][1], pom[10][1];
int num_character[10];
int i;
printf("Enter 10 characters:\n");
for(i=0;i<10;i++){
gets(character[i]);
strcpy(pom[i],character[i]);
num_character[i]=atoi(character[i]);
}
for(i=0;i<10;i++){
if(num_character[i]!=0){
printf("Character '%c' is digit.", pom[i]);
}
else{
printf("Character '%c' is not digit.", pom[i]);
}
putchar('\n');
}
return 0;
}
isdigit()
also does not work after I include ctype
header.