For loop runs infinitely why?

Question

for loop runs infinitely and it prints 1 infinitely when I run the below code.

#include<stdio.h>
#include<conio.h>
void main(){
int i,n;
scanf("%d", &n);
for(i=1;i<=n;i+2){
printf("%d",i);
}
getch();
}

If the input of n= 10

Actual Output:

11111111111111111111111111111111111111111111111111.......

Expected Output:

I want to know why 1 is printed infinitely.

You might want to use a [debugger](https://stackoverflow.com/questions/25385173/what-is-a-debugger-and-how-can-it-help-me-diagnose-problems) for that or look at [How to debug small programs](https://ericlippert.com/2014/03/05/how-to-debug-small-programs/) — Andreas, Sep 02 '19 at 08:10

score 3 · Accepted Answer · answered Sep 02 '19 at 08:11

3

i+2 does not change i, you want i += 2 or i = i + 2

answered Sep 02 '19 at 08:11

mch

1 Answers1