This is a base62 encoded 8 byte random number. The encoding does not matter however, since every random number is encoded differently. It thus boils down on what are the odds that two 8 byte random numbers are the same.
We can generate a total of 28×8=18'446'744'073'709'552'000 values with 8 bytes. So the odds of generating a second value that is the same is 1/18'446'744'073'709'552'000 or 0.000000000000000000542%.
If you generate k items, the odds of generating a duplicate is:
1 - (28×8)!/((28×8-k)!×28×8×k).
As k grows larger, the odds of a collision increase. If you mark the field unique, and thus have a retry mechanism, the odds that it will collide a second time (or a third time) are quite small.