How to override the default comparer for dictionaries?

Question

If I have a dictionary

Dictionary<SomeClass, int> MyDict { get; set; } = ...

how can I override the compare method that gets called when it is evaluating a key?

As in - I want to be in control of which object gets picked when I write

MyDict[SomeClassInstance]

Possible duplicate of [Comparing object used as Key in Dictionary](https://stackoverflow.com/questions/11562996/comparing-object-used-as-key-in-dictionary). [See](https://stackoverflow.com/a/11563134/1797425) this answer as it is what you would need. — Trevor, Sep 03 '19 at 17:31

score 3 · Accepted Answer · answered Sep 03 '19 at 17:14

You need to implement an IEqualityComparer<TKey> and pass an instance of this to the dictionary's constructor:

public class MyComparer : IEqualityComparer<object>
{
    public bool Equals(object o1, object o2)
    {
        // implement your way of equality 
    }
    public int GetHashCode(object o)
    {
        // implement a hash method that returns equal hashes for equal
        // objects and well distributed hashes for not-equal objects
    }
}

Dictionary<object, int> myDict = new Dictionary<object, int>(new MyComparer());

score 0 · Answer 2 · answered Sep 03 '19 at 17:11

0

You would want to use the constructor that allows you to pass in an instance of IEqualityComparer<TKey>, which would then be used for your key comparisons. I don't believe you can change this after instantiation.

answered Sep 03 '19 at 17:11

Jonathon Chase

9,396
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39

you mean derive from ``IEqualityComparer``? sounds weird to me to keep an instance of it – a new one Sep 03 '19 at 17:14
Yes, you would implement `IEqualityComparer` as some class, then pass an instance of that class to the constructor. – Jonathon Chase Sep 03 '19 at 17:14
yeah, that's what the other person said aswell, thanks I'll use that – a new one Sep 03 '19 at 17:20

How to override the default comparer for dictionaries?

2 Answers2