How to get rid of duplicates and their original in array

Question

I am trying to get rid of duplicates from withing a array but I am trying to get rid of the original of those duplicates as well just leaving anything that has not been repeated more than once

Example:

 const jsonarray = [{num: 1}, {num: 1}, {num: 2}, {num: 3}, {num: 5}, {num: 5}];

This is what I want the result to be

 [{num: 2}, {num: 3}];

I have tried splicing with nested for loop but that did not work any help would be appreciated.

If you have tried something, then you must show your work. What happens if someone else says `try X` and you reply `oh I already did try that`. Then you have just wasted their time for nothing. — JK., Sep 04 '19 at 01:15
Note that there's no such thing as a "JSON array". What you are showing there is an array of objects, no JSON involved. JSON is a text format for storing and sending data. — Heretic Monkey, Sep 04 '19 at 01:17
The answer is to [Get all non-unique values (i.e.: duplicate/more than one occurrence) in an array](https://stackoverflow.com/q/840781/215552) and create a separate array of that, then [Remove array of objects from another array of objects](https://stackoverflow.com/q/47017770/215552). — Heretic Monkey, Sep 04 '19 at 01:31

score -1 · Answer 1 · answered Sep 04 '19 at 01:19

var track = jsonarray.length;
for(var i = 0; i < track; i++) {
    var duplicate = false;
    for(var j = 0; j < jsonarray.length; j++) {
        if(i != j && jsonarray[i] == jsonarray[j]) {
            duplicate = true;
            jsonarray.splice(j, 1);
            if(j < i) {
                i--;
                track--;
            }
        }
    }
    if(duplicate) {
        jsonarray.splice(i, 1);
        i--;
        track--;
    }
}

score -1 · Accepted Answer · answered Sep 04 '19 at 01:21

const jsonarray = [{num: 1}, {num: 1}, {num: 2}, {num: 3}, {num: 5}, {num: 5}];

// filter out all the elements that have the same num but different indexes
const filtered = jsonarray.filter((a, indexA) => !jsonarray.find((b, indexB) => b.num === a.num && indexA !== indexB));

console.log(filtered);

How to get rid of duplicates and their original in array

2 Answers2