How to find passing argument value of a running script?

Question

I have an AIX production server, there is a script A.sh running on it. i have no root access for this server. i want to find out argument passing value of this A.sh script. How can i get this value?

Is there any provision inside /proc/processID?

The following is not working. I tried by generating a script:

echo "Hello $1 $2 $3"

while [ 1 ]
do
   sleep 2
   echo $$
done

Then I run this script by

test.sh 1  2 3

Output:

$ cat /proc/3107/cmdline
-bash$

As per suggestion by @Cyrus suggestion I expect

1 2 3

which are the arguments I passed in, but it is not working like that.

On SO we do encourage people to post their efforts in their questions, so kindly do add it in your post and let us know then. — RavinderSingh13, Sep 04 '19 at 04:34
@https://stackoverflow.com/users/3776858/cyrus i want to run on both ubuntu and IBM AIX. in ubuntu for testing purpose. — user3559721, Sep 04 '19 at 05:53
Off: this is the reason why program should overwrite their parameters if they contain confidental data (passwords). — Lorinczy Zsigmond, Sep 04 '19 at 06:40

score 2 · Accepted Answer · answered Sep 04 '19 at 04:52

2

you can try:

cat /proc/PROCESSID/cmdline

answered Sep 04 '19 at 04:52

UtLox

3,744
2
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1

I suggest to append `| tr '\0' ' '`. – Cyrus Sep 04 '19 at 05:18
To exactly get the parameters, exclude the calling program by appending `| cut -d ' ' -f 3-` from the `tr` piped output as told by @Cyrus. For e.g., `cat /proc/$(pgrep -f test.sh)/cmdline | tr '\0' ' ' | cut -d ' ' -f 3-` – sungtm Sep 04 '19 at 06:09

1218985 · Answer 2 · 2019-09-04T06:14:25.197

1

This should work:

cat /proc/3107/cmdline | tr '\0' ' ';

Alternatively you can use:

ps -ef | grep script.sh | grep -v grep

where script.sh is the name of your script which is running now.

Steps for verifying this:

Create a script named script.sh and paste the below code in it:

#!/bin/bash
while :
do
  echo "Press [CTRL+C] to stop.."
  sleep 1
done

Save the file (:wq! from vi editor ).
Make it executable by
```
chmod a+x script.sh
```
Run the script by issuing command-line options like this:
```
./script.sh var1 val1 var2 val2 var2 val4
```
Open another terminal (duplicate session) and issue:
```
ps -ef | grep script.sh | grep -v grep 
```

You should be able to see something like this:

username 12227  2268  0 07:48 pts/98   00:00:00 /bin/bash ./script.sh var1 val1 var2 val2 var2 val4 var4

edited Sep 04 '19 at 06:14

answered Sep 04 '19 at 05:50

1218985

7,531
2
25
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Oh ok, which means your process is not running. Do you see the exit status 1 after issuing the above command? (You can run echo $? to check the exit code). I have updated the steps for creating the script and testing it. You can follow that. – 1218985 Sep 04 '19 at 06:15
@ https://stackoverflow.com/users/1218985/sarath-kumar-sivan this is working in ubuntu but not know about AIX server. Is this solution is worked on AIX IBM ? – user3559721 Sep 04 '19 at 07:56

How to find passing argument value of a running script?

2 Answers2