PHP how to check if variable starts with 'pa_' or not?

Question

I have a variable and i want to check if it starts with 'pa_' how can I do that? i have tried this but it does not work

 $test_str = 'pa_';

 if(substr( $product_attribute['name'], 0, strlen($test_str) ) === $test_str) {
                              $pa_array[]= $product_attribute['name'];
 }

The problem is not with this code - http://sandbox.onlinephpfunctions.com/code/e52dd44d8efb75206bbef1159b2c43c816c413c2 — splash58, Sep 04 '19 at 10:42

ofmiceandmoon · Answer 1 · 2019-09-04T10:42:43.100

1

Just check if pa_ is at the first position of the string

if (strpos($product_attribute['name'], 'pa_') === 0) {
    $pa_array[]= $product_attribute['name'];
}

Try dd($pa_array) within the if-block to see if you even put it in the array.
I quickly tried this and it worked.

edited Sep 04 '19 at 10:42

answered Sep 04 '19 at 10:12

ofmiceandmoon

548
2
9
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Thanks. strangely even though i passed string(8) "pa_color" to it the $pa_array() is empty :( – Sep 04 '19 at 10:24

mgutt · Accepted Answer · 2019-09-04T10:55:42.213

0

Use strpos or access chars in a string by using an offset value:

 $paName = $product_attribute['name'];
 if($paName[0] . $paName[1] . $paName[2] == $test_str) {
     $pa_array[]= $paName;
 }

edited Sep 04 '19 at 10:55

answered Sep 04 '19 at 10:50

mgutt

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PHP how to check if variable starts with 'pa_' or not?

2 Answers2