Is it possible to validate when an entered password is wrong?

Question

When writing an auto-it for safari with selenium, is it possible to know if a password inserted into a website login is wrong?

I've tried using try: and except:, but selenium doesn't raise an error when the password is wrong.

an example would be:

from selenium import webdriver
from selenium.webdriver.common.keys import Keys

driver=webdriver.Safari()
driver.get(r'website')
usr=driver.find_element_by_name(r'username')
usr.clear()
usr.send_keys(r'username')
pas=driver.find_element_by_name(r'password')
pas.clear()
pas.send_keys(r'password')
pas.send_keys(Keys.RETURN)

If you can't shere the website shere the HTML! (include the error of the wrong password) — Moshe Slavin, Sep 04 '19 at 13:38
https://auth.florimont.ch/cas/login?service=https%3A%2F%2Fflore.florimont.ch%2Fhome — a_random_programmer, Sep 04 '19 at 13:42

score 2 · Accepted Answer · answered Sep 04 '19 at 13:48

Use WebDriverWait and element_to_be_clickable and following css selector.

from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC

driver=webdriver.Chrome()
driver.get(r'https://auth.florimont.ch/cas/login;jsessionid=8B5A3B65779756F3CF71ACB41E578AC3?service=https%3A%2F%2Fflore.florimont.ch%2Fhome')
usr=driver.find_element_by_name(r'username')
usr.clear()
usr.send_keys(r'username')
pas=driver.find_element_by_name(r'password')
pas.clear()
pas.send_keys(r'password')
pas.send_keys(Keys.RETURN)
print(WebDriverWait(driver,10).until(EC.element_to_be_clickable((By.CSS_SELECTOR,"#fm1 #msg"))).text)

Print on console:

Invalid credentials.

Browser snapshot:

when i try this i get an error saying that webdriverwait is not defined — a_random_programmer, Sep 04 '19 at 13:52
try now.Sorry I have forgot to update imports initially.Copy entire code now. — KunduK, Sep 04 '19 at 13:53

score 0 · Answer 2 · answered Sep 04 '19 at 14:25

To validate if a username/password inserted into a website login is wrong you can use a try/catch{} block and you can use the following Locator Strategies:

Code Block:

from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.common.exceptions import TimeoutException

chrome_options = webdriver.ChromeOptions()
chrome_options.add_argument("start-maximized")
driver = webdriver.Chrome(options=chrome_options, executable_path=r'C:\Utility\BrowserDrivers\chromedriver.exe')
driver.get("https://auth.florimont.ch/cas/login?service=https%3A%2F%2Fflore.florimont.ch%2Fhome")
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "input#username"))).send_keys("a_random_programmer")
driver.find_element_by_css_selector("input#password").send_keys("a_random_programmer")
driver.find_element_by_css_selector("input.btn-submit").click()
try:
    WebDriverWait(driver, 20).until(EC.text_to_be_present_in_element((By.XPATH, "//h2[text()='Enter your Username and Password']//preceding::div[1]"), "Invalid credentials."))
    print("Invalid Login")
except TimeoutException as e:
    print("Valid Login")
driver.quit()

Console Output:
```
Invalid Login
```

Is it possible to validate when an entered password is wrong?

2 Answers2