java.lang.IllegalArgumentException: No view found for id 0x7f0d0037 for fragment

Question

I'm working on an app where I have to implement the onClick method on the fragment. When a button is clicked I want to open another fragment, but I'm facing an error with fragment id.

I used fragment manager and fragment transaction in the onClick method like below:

override fun onClick(v: View?) {
val fm = childFragmentManager
val ft = fm.beginTransaction()
ft.add(R.layout.fragment_extended_subscribers, ExtendedSubscribersFragment())
ft.addToBackStack(null)
ft.commit()

I also tried to add an id to FrameLayout and add it to fragment transaction but still the same error:

ft.add(R.id.fragment_for_subs,ExtendedSubscribersFragment())

The logcat error is:

java.lang.IllegalArgumentException: No view found for id 0x7f0d0037 (al.mgr.ekranet:layout/fragment_extended_subscribers) for fragment ExtendedSubscribersFragment{d6186df #0 id=0x7f0d0037}

Here is my onCreateView function:

override fun onCreateView(
    inflater: LayoutInflater, container: ViewGroup?,
    savedInstanceState: Bundle?
): View? {
    // Inflate the layout for this fragment
    val view =  inflater.inflate(R.layout.fragment_extended_subscribers, container, false)
    getAllSubscribers()
    return view

Here is the layout associated with the fragment.

<?xml version="1.0" encoding="utf-8"?>
<FrameLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:id="@+id/fragment_for_subs"
    xmlns:tools="http://schemas.android.com/tools"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    tools:context=".homeFragments.ExtendedSubscribersFragment">

    <android.support.v7.widget.RecyclerView
        android:id="@+id/all_subscribers_list"
        android:layout_width="match_parent"
        android:layout_height="match_parent" />

</FrameLayout>

An `R.layout` there is just wrong, and will always throw that Exception. You need to specify the `R.id` for the `ViewGroup` that the `Fragment` is being placed into, not one in the `Fragment`'s own layout. — Mike M., Sep 10 '19 at 07:42
@MikeM. I also tried using id like this: ft.add(R.id.fragment_for_subs,ExtendedSubscribersFragment()) but still the same error — Erald Developer, Sep 10 '19 at 07:45
Yes, you mentioned that in the question. Which layout is `fragment_for_subs` in? — Mike M., Sep 10 '19 at 07:47
Can you please post your `onCreateView` funciton? And the layout as well? — Reaz Murshed, Sep 10 '19 at 07:48
Can you please post your `fragment_extended_subscribers.xml` layout file as well? — Reaz Murshed, Sep 10 '19 at 07:52
"You need to specify the `R.id` for the `ViewGroup` that the `Fragment` is being placed into, not one in the `Fragment`'s own layout." — Mike M., Sep 10 '19 at 07:58
You don't need an example. You already have almost everything. You just need to pass the right `R.id`. Where are you trying to put `ExtendedSubscribersFragment`? — Mike M., Sep 10 '19 at 08:06

MojoJojo · Answer 1 · 2019-09-10T08:21:33.773

-1

try this:

    override fun onClick(v:View?) {
        // Change this to
        //-----------------------
//        val fm = childFragmentManager
        // this
        //-----------------------
        val fm = fragmentManager

        val ft = fm.beginTransaction()
        // Change: layout -> id
        ft.add(R.id.fragment_for_subs, ExtendedSubscribersFragment())
        ft.addToBackStack(null)
        ft.commit()
    }

For more info: link

edited Sep 10 '19 at 08:21

answered Sep 10 '19 at 08:05

MojoJojo

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5
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Please share crash log. – MojoJojo Sep 10 '19 at 08:17
java.lang.IllegalArgumentException: No view found for id 0x7f0d0037 (al.mgr.ekranet:layout/fragment_extended_subscribers) for fragment ExtendedSubscribersFragment{d6186df #0 id=0x7f0d0037} – Erald Developer Sep 10 '19 at 08:20
I again edited my answer, please try this without any change. – MojoJojo Sep 10 '19 at 08:22
still the same, I don't understand this – Erald Developer Sep 10 '19 at 08:33

java.lang.IllegalArgumentException: No view found for id 0x7f0d0037 for fragment

1 Answers1