How to kill bash execution of multiple python scripts if previous one fails?

Question

I have a bash script that executes a number python scripts. Is there a way to prevent the execution of script_2.py if 1_script.py throws back an exception?

#!/usr/bin/bash

python Desktop/code/1_script.py
python Desktop/code/2_script.py
python Desktop/code/3_script.py

Thanks very much!

`python Desktop/code/1_script.py && python Desktop/code/2_script.py ...` — Yevhen Kuzmovych, Sep 10 '19 at 11:36
Possible duplicate of [Automatic exit from bash shell script on error](https://stackoverflow.com/questions/2870992/automatic-exit-from-bash-shell-script-on-error) — Yevhen Kuzmovych, Sep 10 '19 at 11:38
The exception is not important; the fact that an uncaught exception is just one way to produce a non-zero exit status is. — chepner, Sep 10 '19 at 15:37

score 2 · Accepted Answer · answered Sep 10 '19 at 11:37

2

You can simply use && to only execute the next command if the previous one completed succesfully (0 exit code).

#!/usr/bin/bash

python Desktop/code/1_script.py && python Desktop/code/2_script.py && python Desktop/code/3_script.py

answered Sep 10 '19 at 11:37

ruohola

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Thanks very much for the response, I have done a test for when one of the scripts throws an exception on execution with your solution. In this scenario my gitbash terminal just froze and the prompt didn't return. Should the bash script return an error message or what ought to happen if one of the python scripts doesn't run without exception? – Jkennedy559 Sep 11 '19 at 10:37

score -2 · Answer 2 · edited Sep 20 '19 at 10:58

-2

DO step by step At first execute 1_script.py then, execute another python files.

OR

python Desktop/code/1_script.py && python Desktop/code/2_script.py && python Desktop/code/3_script.py

OR

write set -e at the top of your script

"Thanks"

edited Sep 20 '19 at 10:58

Yasen

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answered Sep 10 '19 at 11:47

Sumit Raj

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How to kill bash execution of multiple python scripts if previous one fails?

2 Answers2