Invalid Syntax when F' string dictionary

Question

When I try to f'string dictionary, it says invalid syntax.

def up_low(s):
    d={"upper":0,"lower":0}
    for c in s:
        if c.isupper():
            d["upper"]+=1
            print (f"No. of Upper case characters: {d["upper"]}")
        elif c.islower():
            d["lower"]+=1
            print (f"No. of Lower case characters:{d["lower"]}")
        else:
            pass

it says invalid syntax for line 6 and line 9.

Use single quotes instead of double quotes for your key, like `d['upper']`. The string in which that appears is already in double quotes, so they are in conflict. You could also do the reverse, by single quoting the string instead, but I prefer the single quotes around the key. — Deepstop, Sep 10 '19 at 18:07

DjaouadNM · Answer 1 · 2019-09-10T18:09:06.917

5

Don't use " in a string enclosed with ", either use ', or enclose the string in ':

f"No. of Upper case characters: {d['upper']}"

Or:

f'No. of Upper case characters: {d["upper"]}'

edited Sep 10 '19 at 18:09

answered Sep 10 '19 at 18:07

DjaouadNM

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f-string expression part cannot include a backslash – painor Sep 10 '19 at 18:08

score 0 · Answer 2 · answered Sep 10 '19 at 18:14

Change your double quotes to single quotes inside {d["upper"]}

Here is full working code:

def up_low(s):
    d={"upper":0,"lower":0}
    for c in s:
        if c.isupper():
            d["upper"]+=1
            print (f"No. of Upper case characters: {d['upper']}")
        elif c.islower():
            d["lower"]+=1
            print (f"No. of Lower case characters:{d['lower']}")
        else:
            pass

score 0 · Answer 3 · answered Sep 10 '19 at 18:14

You can use any "other" string delimiter - even the triple ones:

d = {"k":"hello"}
print(f'''{d["k"]}''')
print(f"""{d["k"]}""")
print(f'{d["k"]}')
print(f"{d['k']}")

Output:

hello
hello
hello
hello

Using the same ones confuses python - it does not know where the f-string ends and your key-string starts if you use the same delimiters.

Invalid Syntax when F' string dictionary

3 Answers3

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