Find occurrences where there is a number-number (5-10) in regex

Question

I need to find occurrences where there is a number followed by a hyphen and another number. eg. 5-10,6-12

ExampleString ="a5-10b,48-99z, 6-12, 5-9 ,4-2"
vals =  re.findall(r'(\s\d+\s?)-(\s?\d+\s?)' ,ExampleString)

I need the vals to capture 6-12, 5-9 ,4-2. I am finding it hard to capture only the numbers without the 48-99z. if I remove the question mark in the last \s? it does not capture 4-2 and if I keep it, it captures 48-99z(which I dont need)

Try using a word boundary `\b\d+-\d+\b` https://regex101.com/r/Ui8ChD/1 — The fourth bird, Sep 12 '19 at 16:18

score 5 · Accepted Answer · answered Sep 12 '19 at 16:19

5

You could use the regex (\b\d+-\d+\b). The \b is a word boundary, like a comma, space, start/end of string, etc.

Here's an example: https://www.regexpal.com/?fam=111389

answered Sep 12 '19 at 16:19

OdinX

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score 1 · Answer 2 · edited Sep 12 '19 at 23:05

1

You can apply

re.findall(r'(\d+-\d+)', ExampleString)

Only mention that information within the group that you want extract

Output

['5-10', '48-99', '6-12', '5-9', '4-2']

edited Sep 12 '19 at 23:05

Arco Bast

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answered Sep 12 '19 at 19:03

Maninder

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Find occurrences where there is a number-number (5-10) in regex

2 Answers2