Transform ServletInputStream to String

Question

I am trying to get the body of a HttpServletRequest in a String. What's the best elegant way to do so?

Use `request.getInputStream()` and http://stackoverflow.com/questions/309424/in-java-how-do-a-read-convert-an-inputstream-in-to-a-string — skaffman, Apr 26 '11 at 17:07
I wish I could do that @skaffman, however I must read the request body twice. Once to get a json object and the next one to get the string and I always get stream is already closed. Any thoughts? — tsunade21, Apr 27 '11 at 08:23
tsunade21, your comment doesn't make sense. The answer above tells you how to turn your input stream into a string. Needing to read the same stream twice is very likely a bug. Just use the resulting string in both places. — James Moore, Jul 28 '11 at 22:06
@James Moore, i think i didn't explain myself well before. I had to read the same stream twice because I was using jackson mapping that was reading the stream automatically without giving me any control whatsoever. I finally fixed it, using gson instead of jackson mapping. — tsunade21, Sep 07 '11 at 13:59
@JamesMoore is right, reading the stream twice is a bug. You read a **Stream** from a source you cannot control, from your user's browser. There's simply no way to tell that client "hey, would you send your data once again, please?" — Michael, Jan 05 '14 at 16:25

score 19 · Answer 1 · answered Jun 13 '14 at 07:36

19

String requestStr = IOUtils.toString(request.getInputStream());

answered Jun 13 '14 at 07:36

siledh

score 3 · Answer 2 · answered Oct 13 '16 at 10:58

3

Other way, using Guava:

ByteSource.wrap(ByteStreams.toByteArray(request.getInputStream()))
    .asCharSource(Charsets.UTF_8).read()

See also:

answered Oct 13 '16 at 10:58

Aritz

2 Answers2