LPBYTE buffer = (LPBYTE)calloc(1024, sizeof(char));
std::string res;
I want something like:
res = buffer;
Asked
Active
Viewed 1,227 times
0
João Paulo
- 6,300
- 4
- 51
- 80
sandro98
- 29
- 6
-
Possible duplicate of [Copying non null-terminated unsigned char array to std::string](https://stackoverflow.com/questions/4691608/copying-non-null-terminated-unsigned-char-array-to-stdstring) – Axalo Sep 16 '19 at 14:04
-
What do you want to achieve? Are you looking for `std::string` to own the buffer? Or to hold a copy of its content? – StoryTeller - Unslander Monica Sep 16 '19 at 14:24
1 Answers
1
You can use the std::string constructor (number 6 in the link) that uses iterators to copy the buffer into a string:
std::string res(buffer, buffer + 1024);
Note that there is no conversion other than the unsigned chars in your buffer being converted to chars in the std::string.
Ted Lyngmo
- 93,841
- 5
- 60
- 108
-
Note that the buffer is copied as-is without any conversion from possibly non-textual format. This may or might not be was intended by "convert to string". – eerorika Sep 16 '19 at 14:30
-