How to get IP address of the client who made request to python SimpleHTTPServer?

Question

I am setting python local server using python -m SimpleHTTPServer, I made that server publicly available using ngrock and have some public IP address like http://2ee94---.ngrok.io. Now I am making the request to the public IP address. I want to get IP address from request. But I am getting the only status in the terminal. How to get details (IP address of client) of the request.

HTTP Requests                                                                   
-------------                                                                   

GET  /                         200 OK                                           
GET  /                         200 OK

IP address of the client, who is making a request to the server. — Akshay Bande, Sep 17 '19 at 12:00
`SimpleHTTPServer` is, well, *simple*. Probably you want a more full-featured server…!? — deceze, Sep 17 '19 at 12:01
Possible duplicate: https://stackoverflow.com/questions/37055005/how-to-get-client-ip-from-simplehttpserver — Kostas Charitidis, Sep 17 '19 at 12:06
Possible duplicate of [How to get client IP from SimpleHTTPServer](https://stackoverflow.com/questions/37055005/how-to-get-client-ip-from-simplehttpserver) — Maurice Meyer, Sep 17 '19 at 12:23

score 0 · Accepted Answer · answered Nov 13 '19 at 16:25

I got it done after setting up my own handler class,

import SimpleHTTPServer
import SocketServer


class MyHandler(SimpleHTTPServer.SimpleHTTPRequestHandler):
    def handle_one_request(self):
        print(self.client_address[0])
        return SimpleHTTPServer.SimpleHTTPRequestHandler.handle_one_request(self)

httpd = SocketServer.TCPServer(("", 8080), MyHandler)

while True:
    httpd.handle_request()

How to get IP address of the client who made request to python SimpleHTTPServer?

1 Answers1

Linked