str_replace_all Error: `replacement` must be a character vector

Question

What is the simplest way to replace patterns in a mixed vector?

vec <- c(0, 2500, "A", "B", 2, 3, "M", "+", "\"\"")

library(stringr)

vec <- str_replace_all(vec, c("A" = 0, "B" = 9, "M" = 6, "+" = 0, "\"\"" = 0))

Error: `replacement` must be a character vector

Expecting this vector:

[1] "0" "2500" "0" "9" "2" "3" "6" "0" "0"

Possible duplicate of [Replace specific characters within strings](https://stackoverflow.com/questions/11936339/replace-specific-characters-within-strings) — slava-kohut, Sep 17 '19 at 15:53
`vec <- c(0, 2500, "A", "B", 2, 3, "M") gsub("A", "0", vec)` — slava-kohut, Sep 17 '19 at 15:55

score 0 · Accepted Answer · edited Jan 18 '22 at 11:50

0

use quotationmarks in the replacements as str_replace_all expects a string as a replacement:

vec <- str_replace_all(vec, c("A" = "0", "B" = "9", "M" = "6", "+" = "0", "\"\"" = "0"))

edited Jan 18 '22 at 11:50

ah bon

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answered Sep 17 '19 at 15:55

saae

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So obvious! Thank you! – Danilo Correa Sep 17 '19 at 16:52

str_replace_all Error: `replacement` must be a character vector

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