I tried using $(date)in my bash shell script, however I want the date in YYYY-MM-DD +DAY + Mounth format.(if the month is 9 I do not want to display 09) How do I get this?
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Piccolo
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2Possible duplicate of [Convert date formats in bash](https://stackoverflow.com/questions/6508819/convert-date-formats-in-bash) – oguz ismail Sep 17 '19 at 20:04
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So would today be `2019-09-17 +17 +9`? – chepner Sep 17 '19 at 20:06
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2019-09-17 Tuesday September ,but I want to display in whatever language I want. I have this : `date "+%A %B %d %T %y" ` – Piccolo Sep 17 '19 at 20:07
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Hmm, so where does the _if the month is 9 I do not want to display 09_ come to picture? – James Brown Sep 17 '19 at 20:09
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Some versions of date can't display the month without the leading zero. You can use sed to remove it, though: the month is the only number surrounded by dashes:
date '+%Y-%m-%d %A %B' | sed 's/-0\([0-9]\)-/-\1-/'
Some versions support the padding modifiers. To turn padding off, use a dash:
date '+%Y-%-m-%d %A %B'
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To change the language, just specify the locale:
$ LC_ALL=it_IT.UTF-8 date '+%Y-%m-%d %A %B' | sed 's/-0\([0-9]\)-/-\1-/'
2019-9-17 martedì settembre
choroba
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One more question. What can i do when i have the code in this format`LC_ALL=it_IT.UTF-8 date '+%Y-%m %B-%d %A' | sed 's/-0\([0-9]\)-/-\1-/' ` – Piccolo Sep 17 '19 at 20:23
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Either specify `%-m` if your version of `date` supports it, or remove the dash between a digit and zero: `sed 's/\([0-9]\)-0/\1-/'`. – choroba Sep 17 '19 at 20:28