Why I can't use tex2D inside a loop in Unity ShaderLab?

Question

I am trying to do something like

   while (currentLayerDepth < currentDepth)
   {
       currentUV -= step;
       currentDepth = tex2D(_HeightTex,currentUV).a;
       currentLayerDepth += eachLayer;
   }

It logged a error Shader error in 'Unlit/CustomParallax': unable to unroll loop, loop does not appear to terminate in a timely manner (1024 iterations) at line 76 (on metal) So now I have two choices, one is to add [unroll(100)] to limit loop times and the other is using tex2Dlod instead of tex2D.

I'm curious why this happened？

Besides, why tex2Dlod can be used in a loop?

score 3 · Accepted Answer · answered Sep 18 '19 at 14:38

3

tex2D has to compute a local derivative to determine the correct LOD for the sample. Because of how derivatives are usually computed (as difference between neighbouring computation units), they can only be computed for predictable control flow.

Your loop doesn't predictably do the same number of calls to tex2D for neighbouring fragments, so the derivative can't be predictably computed.

For more details have a look at the GLSL specs. Search for "derivative" and "uniform control flow"

answered Sep 18 '19 at 14:38

Tiberiu Maran

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I don't think I get your answer, could you explain more? – OtakuFitness Sep 19 '19 at 03:29
1

"3.8.2. Dynamically Uniform Expressions and Uniform Control Flow" from the GLSL specs I linked above elaborates on how different instances of the shader are executed at the same time, and the flow is "uniform" only when the same instruction is called in all instances of the shader. `tex2D` can only be called from "uniform control flow" because it has to compute the LOD, by computing a "derivative". `tex2Dlod` doesn't because you provide the LOD. – Tiberiu Maran Sep 19 '19 at 06:55

Why I can't use tex2D inside a loop in Unity ShaderLab?

1 Answers1