findall string that starts with letter "CU" and return full string

Question

It seems like straight forward thing however could not find appropriate SO answer.

I have a column called title which contain strings. I want to find out rows that starts with letter "CU".

I've tried using df.loc however It's giving me indexError,

Using regex, re.findall(r'^CU', string) returns 'CU' instead of full name ex: 'CU abcd'. How can I get full name that starts with 'CU'?

EDIT: SORRY, I did not notice it was a duplicate question, problem solved by reading duplicate question.

Answer 1

You can try:

string.startswith("CU")