Time of the current day in seconds in Python

Question

I know how to get time of the current day in seconds

import time
seconds=time.time() % 86400

However the result is valid for UTC. Is there elegant way to do that for local time? I am aware I could get that somehow from local time struct_time, but it will be rather complicated procedure. Is there any elegant way to do that?

Add the timezone offset to `time.time()` before getting the modulus. — Barmar, Sep 19 '19 at 16:55
Perhaps you could look at this answer: https://stackoverflow.com/a/15971505/8935887 — Brian Ton, Sep 19 '19 at 16:55
Can you post some example so that the answer is specific to the problem statement. — abheet22, Sep 19 '19 at 16:55
@Barmar The problem is that offset is changing due to summer saving time. — Pygmalion, Sep 19 '19 at 16:56
@Pygmalion does that mean you are strictly looking for a solution in `time`, not `datetime` module? — r.ook, Sep 19 '19 at 17:25

score 1 · Answer 1 · answered Sep 19 '19 at 17:06

1

It's not complicated to get it from struct_time.

t = time.localtime()
secs = 3600 * t.tm_hour + 60 * t.tm_min + t.tm_sec

answered Sep 19 '19 at 17:06

Barmar

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I guess this is less complicated than https://stackoverflow.com/questions/19289016/is-there-an-easy-way-to-get-the-current-time-difference-between-the-current-time – Pygmalion Sep 19 '19 at 17:09
I expected there should be something simpler and seconds are rounded to integer. – Pygmalion Sep 19 '19 at 17:11
1

If you want the fraction you can add `math.modf(time.time())[0]` – Barmar Sep 19 '19 at 17:20
Or perhaps add `time.time() % 1`? – Pygmalion Sep 19 '19 at 17:32

Time of the current day in seconds in Python

1 Answers1