I'm trying to make an addition of the 2 following numbers:
v1 = 0.005919725632510221
v2 = 0.9940802743674898
v1+v2
Result always = 1
Why ?
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The difference between their values and 1 is too small to be represented. If both numbers started out, say, 10^20 times larger than they are currently, you could use BigInt. (maybe there's a library for decimal manipulation too) – CertainPerformance Sep 20 '19 at 07:45
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Re "always" -- if you repeat the same operation, of course you're going to get the same result. As for why adding those numbers gives you 1, see the [linked question](https://stackoverflow.com/questions/588004/is-floating-point-math-broken)'s answers. – T.J. Crowder Sep 20 '19 at 07:45
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Just for the curious the result is: `1.000000000000000021` – Roland Starke Sep 20 '19 at 07:51
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@RolandStarke - You mean mathematically, right? Because it exceeds the precision of IEEE-754 double-precision floating point. The value is actually 1 in IEEE-754 double-precision floating point, not just a number very near 1. – T.J. Crowder Sep 20 '19 at 08:25
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@T.J.Crowder Mm yes sry, meant mathematically. (Now that you say it, i just add confusion and waste peoples time.) – Roland Starke Sep 20 '19 at 08:33
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@RolandStarke - That's a bit harsh. :-) Have a good one! – T.J. Crowder Sep 20 '19 at 08:52