I want to split a string after a specific length without cut any words, not equal String

Question

I want to split a string Like 'Rupees Two Hundred Forty One and Sixty Eight only' when its length is at 35, I want to split this string in 2. I tried this code to split the string.

String text = "Rupees Two Hundred Forty One and Sixty Eight only";
List<String> parts = new ArrayList<>();
int length = text.length();
for (int i = 0; i < length; i += 35) {
    parts.add(text.substring(i, Math.min(length, i + size)));

but the output is like this.

[Rupees Two Hundred Forty One and Si, xty Eight only]

But I want to split the string like this.

[Rupees Two Hundred Forty One and, Sixty Eight only]

There is no cut word when splitting the string. The string varies every time according to the bill amount.

Answer 1

You may not be able to do it exactly. But use String.indexOf() to find the first space starting at 35. Then use the substring method to divide the string.

      String text = "Rupees Two Hundred Forty One and Sixty Eight only";
      int i = text.indexOf(" ", 35);
      if (i < 0) {
         i = text.length();
      }
      String part1 = text.substring(0,i).trim();
      String part2 = text.substring(i).trim();

Here is an alternative method. It has not been fully checked for border cases.

      String[] words = text.split(" ");
      int k;
      part1 = words[0];
      for (k = 1; k < words.length; k++) {
         if (part1.length() >= 35 - words[k].length()) {
            break;
         }
         part1 += " " + words[k];
      }
      if (k < words.length) {
         part2 = words[k++];
         while (k < words.length) {
            part2 += " " + words[k++];
         }
      }
      System.out.println(part1);
      System.out.println(part2);

Answer 2

Just search for a preferred position at the i+35 position. One thing to consider, is what should happen when there is no such position, i.e. a word exceeds the specified size. The following code will enforce the size limit, breaking in the middle of the word if no good position could be found:

List<String> parts = new ArrayList<>();
int size = 35, length = text.length();
for(int i = 0, end, goodPos; i < length; i = end) {
    end = Math.min(length, i + size);
    goodPos = text.lastIndexOf(' ', end);
    if(goodPos <= i) goodPos = end; else end = goodPos + 1;
    parts.add(text.substring(i, goodPos));
}

If the break happened at a space character, the space will be removed from the result strings.

Answer 3

you can find index of "and" and substring the string from 0 to index of "and".

 int i = text.indexOf("and") + 3;
 String part1 = text.substring(0,i);
 String part2 = text.substring(i).trim();

Answer 4

I would start building the String from the scratch using StringBuilders. An example with some comments inside:

    String text = "Rupees Two Hundred Forty One and Sixty Eight only For seven thousand chickens";
    String split[] = text.split(" "); // Split by space
    // One SB for each sentence
    StringBuilder sentence = new StringBuilder();
    // One SB for the total String
    StringBuilder total = new StringBuilder();
    for (int i = 0; i < split.length; i++) {
        String word = split[i];
        // Check if that words fits to sentence
        if (sentence.length() + word.length() <= 35) {
            sentence.append(word);
            sentence.append(" ");
        } else {
            total.append(sentence.toString().trim());
            total.append(", ");
            // Flush sentence to total and start next sentence
            sentence = new StringBuilder();
            sentence.append(word);
            sentence.append(" ");
        }
    }
    //Add any leftover
    if (sentence.length() > 0)
        total.append(sentence.toString().trim());
    System.out.println(total.toString());

Which outputs to:

Rupees Two Hundred Forty One and, Sixty Eight only For seven thousand, chickens

Answer 5

I think you can use while loop to count words holding last faced space character:

public static List<String> split(String str, int length) {
    List<String> res = new ArrayList<>();
    int prvSpace = 0;
    int from = 0;

    while (prvSpace < str.length()) {
        int pos = str.indexOf(' ', prvSpace + 1);

        if (pos == -1) {
            res.add(str.substring(from));
            prvSpace = str.length();
        } else if (pos - from < length)
            prvSpace = pos;
        else {
            res.add(str.substring(from, prvSpace));
            from = prvSpace + 1;
        }
    }

    return res;
}

---

Demo:

in: "RupeesTwoHundredFortyOneandSixtyEightonly"
out: ["RupeesTwoHundredFortyOneandSixtyEightonly"]

in: "Rupees Two Hundred Forty One and Sixty Eight only"
out: ["Rupees Two Hundred Forty One and", "Sixty Eight only"]

Answer 6

I found an alternative using Apache commons-lang3:

import java.util.Arrays;
import org.apache.commons.lang3.StringUtils;
import org.apache.commons.lang3.text.WordUtils;

class Example {

    public static void main(String[] args) {
        String text = "Rupees Two Hundred Forty One and Sixty Eight only";
        String wrappedText = WordUtils.wrap(text, 35, "\n", false);
        String[] lines = StringUtils.split(wrappedText, "\n");
        System.out.println(Arrays.asList(lines));
        // Outputs [Rupees Two Hundred Forty One and, Sixty Eight only]
    }
}

NB. If your input has line feeds, best remove them.