md5 hex to binary in python

Question

i read many answers about converting hex to binary in SO. I tried to implement it with md5:

import hashlib

c = hashlib.md5("123hello123".encode('ascii'))
print(c.hexdigest())
for _hex in c.hexdigest():
    _hex = int(_hex, 16)
    print(bin(_hex)[2:], end="")

i get the output:

b303fa684382db471658016690101792 1011110111111101011010001001110001011011011100111111010110000111011010010101111100110

where as when i convert in an online converter i get:

10110011000000111111101001101000010000111000001011011000000000000000000000000000000000000000000000000000000000000000000000000000

what is the right answer? how should i correct my program?

You need to pad each hex digit's binary representation to 4 characters. — Aran-Fey, Sep 20 '19 at 17:38
_Both_ of these results look wrong. The one you got from the converter translates to `b303fa684382d8000000000000000000`. — Kevin, Sep 20 '19 at 17:41

score 2 · Accepted Answer · answered Sep 20 '19 at 17:41

2

The bin function does not include leading zeros, while each hex character always represents 4 binary digits. bin(_hex)[2:].rjust(4,"0") will work.

answered Sep 20 '19 at 17:41

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While you're at it, you may as well skip the loop entirely and call `bin` on the entire hex digest just once: `print(bin(int(c.hexdigest(), 16))[2:].rjust(128, "0"))` – Kevin Sep 20 '19 at 17:47
@Kevin that is worth turning into a separate answer. – Mark Ransom Sep 20 '19 at 17:48

md5 hex to binary in python

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