Return number of arguments function is called with?

Question

How do I create a function that returns the number of argument/s it was called with.

Examples:

numArgs() ➞ 0

numArgs("foo") ➞ 1

numArgs("foo", "bar") ➞ 2

numArgs(true, false) ➞ 2

numArgs({}) ➞ 1

My code

function numArgs() {

}

`arguments.length` or use rest syntax and do the same thing, `numArgs = (...args) => args.length` — CertainPerformance, Sep 22 '19 at 06:39
function numArgs(...var_args) { return var_args.length; } than call numArgs(5,1,3,6,7); it'll return no of argument. you can pass any no of argument to test it. — shreya_js, Nov 28 '19 at 15:49

score 1 · Answer 1 · answered Sep 22 '19 at 06:45

1

You can use the

function.length

or

arguments.length

hope this helps.

answered Sep 22 '19 at 06:45

iamimran

Mesar ali · Accepted Answer · 2019-09-22T06:46:45.467

0

you can use arguments.length as defined by MDN

function numArgs() { 
  return arguments.length;
}

edited Sep 22 '19 at 06:46

answered Sep 22 '19 at 06:40

Mesar ali

2 Answers2