How to avoid evaluating an GString

Question

I'm working on extending a legacy script system using groovy. The source scripts are "java-like", so it mostly parses as a groovy script with a little pre-processing.

I'm using invokeMethod() and missingMethod() to pass-through the legacy code, enabling me to use closures and other groovy features to enhance the scripts. However, the original script uses strings of the type "$foo" to refer to variables. When a legacy method is caught by missingMethod(), I need it to not evaluate this string as a GString, but simply outputting it verbatim. Is this possible in any way?

I am not sure if i got this correctly, but why don't you escape GStrings in the pre-processing step? — Andre Steingress, Apr 28 '11 at 06:00
What you suggest, e.g. escaping the '$'s in preprocessing, is what I've ended up with so far. — Jo-Herman Haugholt, Apr 28 '11 at 08:13

score 7 · Accepted Answer · answered May 17 '11 at 07:24

there are two way to escape the $foo:

escape the '$' as '\$'
use ' instead of " as string delimiter

example:

 def test = "bad"
 def s0 = "$test"
 def s1 = "\$test"
 assert s1 != s0
 def s2 = '$test'
 assert s2 == s1
 println s0
 println s1
 println s2

So I guess you have to use your preprocessor in order to escape your strings

How to avoid evaluating an GString

1 Answers1