I want to write a bash script that takes a user input (which will be a filename) and replaces a path to a file inside a css file with that filename. For simplicity, the two files will be in the same folder and in the css code only the filename at the end of the path should be changed.
I thought of using regex to match any line of code that has a specific pattern and then change the end of it. I know about sed, but since the filename always changes I'm not sure how to solve this problem other than regex. I also thought of adding a variable in the css file that holds the filename as a value and then adding that variable at the end of the path, but I'm not sure then how to access that variable from a bash script.
Any recommendations on how to tackle this problem?
Thanks!
Edit Adding more Information: Here is the line in the css file I want to edit. The part to be changed is the fileName.png at the end. Since it will change I thought of using a regex to "find" the correct spot in the css file.
background: #2c001e url(file:////usr/share/backgrounds/fileName.png/);
A regex matching only this line in this specific file is the following. It could probably be simplified, but I don't see a reason why since it should work too:)
(background)\:\s\#.{6}\s(url)\((file)\:\/{4}(usr)\/(share)\/backgrounds\/.+\.(png)\/\)\;