How can I merge two string lists?

Question

I have now two lists

a = ['Redemption', 'The', 'II', 'Dark']
b = [912, 813, 230, 567]

I would like to have a result of,

c = 
Redemption 912  
The 813
II 230
Dark 567

The code below is what I have tried but the output is incorrect:

aa = [a[i] for i in range(10)]
bb = [str(b[j]) for j in range(10)]

for i in aa:
    for j in bb:
        c = i + ' ' + j
    print(c)

Result is

Redemption 567
The 567
II 567
Dark 567

Use [`zip()`](https://docs.python.org/3.7/library/functions.html#zip) `for x, y in zip(a, b):print(f'{x} {y}'})` — Steven Rumbalski, Sep 24 '19 at 14:31
The most Pythonic way is to use [zip()][1] [1]: https://docs.python.org/3.3/library/functions.html#zip — EzzatA, Sep 24 '19 at 14:32

score 0 · Accepted Answer · answered Sep 24 '19 at 14:34

0

You only need a single for loop if you are matching elements on the same index, assuming the lists are the same length.

Try this:

a = ['Redemption', 'The', 'II', 'Dark']
b = [912, 813, 230, 567]

for i in range(len(a)):
    print(a[i],b[i])

answered Sep 24 '19 at 14:34

Stephen

2

This works, but it is uglier and slower than the pythonic solution of using `zip()`. – Steven Rumbalski Sep 24 '19 at 14:36
Thanks! A further question, how could the output be sorted in descending order by the b list? ie, Redemption 912 The 813 Dark 567 II 230 – goxywood Sep 24 '19 at 14:46
@goxywood You can use zip() and sorted() to do that all in one line: c = sorted(zip(a, b), key=lambda z: z[1], reverse=True) – Stephen Sep 24 '19 at 15:02

1 Answers1