implement sorting for list of dictionary having versions as key in python

Question

I'm trying to use StrictVersion on the code below:

from distutils.version import StrictVersion
from operator import itemgetter

v = [{'ver': '1.1.12'},{'ver': '1.0.0'},{'ver': '1.3.3'},{'ver': '1.0.12'},{'ver': '1.0.2'}]
v.sort(key=itemgetter("ver"),reverse=True)

This is sorting based on version with below code but it's not sorting properly in above code.

versions = ["1.1.2", "1.0.0", "1.3.3", "1.0.12", "1.0.2"]
versions.sort(key=StrictVersion,reverse=True)

How to use key=StrictVersion on above with key? Or is there an alternative?.

Do you want `v.sort(key=lambda x: StrictVersion(x['ver']),reverse=True)`? — Chris, Sep 25 '19 at 06:59
I don't think you need `StrictVersion` strictly for this sorting. `sorted(v, key = lambda x: x['ver'], reverse = True)`. — Sayandip Dutta, Sep 25 '19 at 07:07
`v.sort(key = lambda x:StrictVersion( x['ver']),reverse=True)` — Onyambu, Sep 25 '19 at 07:17

score 2 · Answer 1 · answered Sep 25 '19 at 07:08

2

all the keys are the same, how do you intend on sorting the keys when they all are the same?

for the version part you can sort using:

list_to_sort = ['1.1.4', '1.6.9', '1.1.2']
sorted(list_to_sort, key=lambda version: int(''.join(["%02X" % int(i) for i in version.split('.')]), 16))

answered Sep 25 '19 at 07:08

pythonPleasue

68
8

its not only list, its list of dictionary with key,value pair. this will not work for me. – Vijaysinh Parmar Sep 25 '19 at 07:12

score 2 · Accepted Answer · answered Sep 25 '19 at 07:19

2

v.sort(key = lambda x:StrictVersion( x['ver']),reverse=True)
[{'ver': '1.3.3'},
 {'ver': '1.1.12'},
 {'ver': '1.0.12'},
 {'ver': '1.0.2'},
 {'ver': '1.0.0'}]

answered Sep 25 '19 at 07:19

Onyambu

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implement sorting for list of dictionary having versions as key in python

2 Answers2