How to open multiple files in loop, in python

Question

I'm new to python. I'm want to open multiple files in Python. I'm can open each of them with open() function. I'm not sure about formatting.

with open("/test/filename.css", "r") as f:
     s = f.readlines()
     print(s)

I'm can open one file, but I'm not sure how to open multiple files. This is the code that I have. In live_filename() function have many files.

inputfiles = live_filename()
    for live in inputfiles:
        with open("/test/............. .css, "r") as f:

I don't know how to put code formatting in space. and I think the live variable is a tuple can't concatenate str. what should i do?

Please edit your question to include a sample input by `print`ing the return value of `live_filename()`. — Selcuk, Sep 26 '19 at 03:00
@lalin Edit your question to show us the result of `print(inputfiles)` — OverLordGoldDragon, Sep 26 '19 at 03:06
Possible duplicate of [How can I open multiple files using "with open" in Python?](https://stackoverflow.com/questions/4617034/how-can-i-open-multiple-files-using-with-open-in-python) — Ramesh, Sep 26 '19 at 03:09

OverLordGoldDragon · Accepted Answer · 2019-09-26T03:24:33.660

5

Open each just as you did for one, and then append them to a list:

import os

folderpath = r"D:\my_data" # make sure to put the 'r' in front
filepaths  = [os.path.join(folderpath, name) for name in os.listdir(folderpath)]
all_files = []

for path in filepaths:
    with open(path, 'r') as f:
        file = f.readlines()
        all_files.append(file)

Now, all_files[0] holds the first file loaded, all_files[1] the second, and so on.

UPDATE: for all files in the same folder: first, get the folder path (on Windows, like this). Suppose it's "D:\my_data". Then, you can get all the filepaths of the files as in the script above.

edited Sep 26 '19 at 03:24

answered Sep 26 '19 at 03:04

OverLordGoldDragon

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I got it. I make it in function live_filename(). Do I have to do it again? – Sep 26 '19 at 03:27
@lalin Just make sure `filepaths` contains all paths of files you plan to load - you can check via `print(filepaths)`. If so, no need to repeat. – OverLordGoldDragon Sep 26 '19 at 03:29
I got it. I will try this. :) – Sep 26 '19 at 03:31
I try this.but error show ==> expected str, bytes or os.PathLike object, not tuple – Sep 26 '19 at 03:39
@lalin If you didn't change your `live_filename()` and it has the same output, then that is the problem. Just don't use it - instead follow my answer instructions step-by-step. – OverLordGoldDragon Sep 26 '19 at 03:44
@ Okay. I will try again. :) – Sep 26 '19 at 03:46
I can do it. Thank you very much :))))) – Sep 26 '19 at 04:17
@lalin Congrats. Consider [accepting](https://puu.sh/ElDqq/cd2cee0310.png) the answer – OverLordGoldDragon Sep 26 '19 at 13:51

MjZac · Answer 2 · 2019-09-26T04:11:11.630

1

You can do like this:

folder = "..." # Absolute path to folder in which the files reside
files_to_read = [("filename.css","FileName"),( "filename2.css","Filename2")]
for (file, _) in files_to_read:
    filepath = os.path.join(folder, file)
    with open(filepath, "r") as f:
        s = f.readlines()
        print(s)

edited Sep 26 '19 at 04:11

answered Sep 26 '19 at 03:03

MjZac

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I got it, but if I have 100 files. what should i do? – Sep 26 '19 at 03:06
@lalin Are all these files in the _same folder_? – OverLordGoldDragon Sep 26 '19 at 03:07
@OverLordGoldDragon Yes in the same folder. – Sep 26 '19 at 03:09
@lalin Do you want it to be processed in parallel? You are receiving file paths from a function right? Can you show a sample output of `live_filename()` – MjZac Sep 26 '19 at 03:10
@MjZac Yes I receiving file paths from a function. output is : ('home', 'Home') ('fun', 'Fun') – Sep 26 '19 at 03:18
Then it's just `for (file, _) in live_filename():` – tripleee Jan 02 '21 at 10:02

How to open multiple files in loop, in python

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