Why does the variable t not calculate properly?

Question

The variable t keeps going to zero.

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score 3 · Accepted Answer · answered Oct 02 '19 at 17:23

The problem is here:

t *= ((n-1)/((2*n)-1))

n is integer. When you perform arithmetic operations on an integer, the result is also an integer (i.e. gets truncated).

To make the division into a float-point one, you need to convert one of the operands to a floating-point type, for example like so:

t *= ((n-1)/(float)((2*n)-1))

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