reading terminal in python not the same

Question

import os
from subprocess import PIPE,Popen
#os.chdir("..")
cmd=["ls","*.py"]

try:
    p=Popen(cmd,stdout=PIPE,universal_newlines=True,shell=True)
except Exception as e:
    print(f"Exception:\t{e}")
for line in p.stdout:
    print(line,end=" ")
p.stdout.close()
return_code=p.wait()

I am trying to get ls all python files in my server, however whenever I am writing the output which should be all .py files only, I am getting every file there, what am I doing wrong. I tried ls *.py in server terminal and it works fine,however in script not working

Not a solution, but why are you using `Popen` instead of `run`? — Dan, Oct 03 '19 at 16:04

score 1 · Accepted Answer · answered Oct 03 '19 at 16:05

1

You can directly use "ls *.py" as a command

import os
from subprocess import PIPE,Popen
#os.chdir("..")
cmd=["ls *.py"]

try:
    p=Popen(cmd,stdout=PIPE,universal_newlines=True,shell=True)
except Exception as e:
    print(f"Exception:\t{e}")
for line in p.stdout:
    print(line,end=" ")
p.stdout.close()
return_code=p.wait()

answered Oct 03 '19 at 16:05

Vikas Mulaje

727
6
11

this works, but in docs the used list elements to show spaces – Piggydog Oct 03 '19 at 16:08
@Piggydog When you use `shell=True`, the command is given to the shell as a single string. – Barmar Oct 03 '19 at 16:09
If you use a list, it just sends the first element to the shell. – Barmar Oct 03 '19 at 16:09
Although the documentation doesn't seem to mention this. – Barmar Oct 03 '19 at 16:10

reading terminal in python not the same

1 Answers1