How do you get the output from a command?
For simplicity:
$proc = Start-Process ls -PassThru -Wait -ArgumentList '-a'
$OutPut = $proc.StandardOutput.ReadToEnd()
Error:
<Error retrieving property - InvalidOperationException>
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Chris G.
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It doesn't have to be that hard. `$output = ls -a` – js2010 Oct 04 '19 at 13:25
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Thanks, but it was just for simplicity - I have way more for the ArgumentList :-) – Chris G. Oct 04 '19 at 13:28
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Why would that matter? – js2010 Oct 04 '19 at 14:10
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Need to use double "--" in parameters and it looks like it only works with Start-Process – Chris G. Oct 04 '19 at 14:12
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It should work. – js2010 Oct 04 '19 at 14:19
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Glad to hear, can you make this work: export IP_ADDRESS=$(kubectl get svc $INGRESSGATEWAY --namespace istio-system --output 'jsonpath={.status.loadBalancer.ingress[0].ip}') – Chris G. Oct 04 '19 at 14:23
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There's no export in powershell. If this doesn't work, maybe you should post another question: `$env:IP_ADDRESS = kubectl get svc $INGRESSGATEWAY --namespace istio-system --output 'jsonpath={.status.loadBalancer.ingress[0].ip}'` – js2010 Oct 04 '19 at 14:25
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Thanks I know, but the question is simplified to break it down. Thanks for your suggestion. – Chris G. Oct 04 '19 at 14:28
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And you are right, I should note what the overall problem is - I will elaborate on this - thanks – Chris G. Oct 04 '19 at 14:30