Opening two files simultaneously on a "with" context

Question

I'm wondering if there is a construction in Python 3 that allows me to open two (or more) files on the same with context.

What I'm looking for is something like this:

from pathlib import Path

file1 = Path('file1.txt')
file2 = Path('file2.txt')

with file1.open() as f1 and file2.open() as f2:
    '''do something with file handles...

The code above is obviously invalid, which leads to this question.

sanyassh · Accepted Answer · 2019-10-06T16:28:28.470

9

Use comma:

from pathlib import Path

file1 = Path('file1.txt')
file2 = Path('file2.txt')

with file1.open() as f1, file2.open() as f2:
    '''do something with file handles...

Documentation for with statement covers the case for multiple context expressions.

edited Oct 06 '19 at 16:28

answered Oct 06 '19 at 16:23

sanyassh

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Thanks, @sanyash. Extra bonus for pointing me the documentation. :-) – accdias Oct 06 '19 at 16:39

buran · Answer 2 · 2019-10-06T16:30:59.573

3

The correct one is with file1.open() as f1, file2.open() as f2:

Depending on what you want to do with f1 and f2 you can use directly pathlib.Path.read_text() and pathlib.Path.write_text(), e.g.

from pathlib import Path

file1 = Path('file1.txt')
content = file1.read_text()
print(content)

edited Oct 06 '19 at 16:30

answered Oct 06 '19 at 16:25

buran

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Thanks. I'm used to ```pathlib.Path()``` methods. My interest was on the ```with``` context. – accdias Oct 06 '19 at 16:34

Opening two files simultaneously on a "with" context

2 Answers2