How to add variable inside the cout?

Question

I want to add float average variable inside the cout. What's the perfect way for it?

int first , second , third;
cout<<"enter the first number: ";
cin>>first;
cout<<"enter the second number: ";
cin>>second;
cout<<"enter the third number: ";
cin>>third;

cout<<float average=(first+second+third)/3;

Related: https://stackoverflow.com/q/64782/1025391 and https://stackoverflow.com/q/41364181/1025391 — moooeeeep, Oct 08 '19 at 07:21
And because this might come up in the future too: https://stackoverflow.com/q/3602827/1025391 — moooeeeep, Oct 08 '19 at 07:23

score 1 · Accepted Answer · answered Oct 08 '19 at 07:18

You can't do that. Just declare the variable before printing it.

float average = (first + second + third) / 3;
std::cout << average;

What you can do, however, is just not having the variable at all:

std::cout << (first + second + third)/3;

Also note that the result of (first+second+third)/3 is an int and will be truncated. You might want to change int first, second, third; to float first, second, third; if that's not your intention.

score 1 · Answer 2 · answered Oct 08 '19 at 07:18

1

float average=(first+second+third)/3; cout<<average OR

cout<<((first+second+third)/3)

answered Oct 08 '19 at 07:18

MubashirEbad

289
1
7

score 1 · Answer 3 · answered Oct 08 '19 at 07:24

You need to declare the variable type first.

You can do something like this.

int first , second , third;
cout<<"enter the first number: ";
cin>>first;
cout<<"enter the second number: ";
cin>>second;
cout<<"enter the third number: ";
cin>>third;

float average;

cout<< (average=(first+second+third)/3);

score 0 · Answer 4 · answered Oct 08 '19 at 07:17

0

C++ way would be:

float average = static_cast<float>(first + second + third) / 3.;
std::cout << average << std::endl;

answered Oct 08 '19 at 07:17

carobnodrvo

1,021
1
9
32

The addition may overflow, might be better to divide before addition. – Empty Space Oct 08 '19 at 07:25

How to add variable inside the cout?

4 Answers4