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I have a vector of integers with 'discountinuities' and I would like to convert in a list of vectors with consecutive values

Example 

vec = c(1,2,5,7,8,9,11,12,13,15)
[1]  1  2  5  7  8  9 11 12 13 15

Expected output:

[[1]]
[1] 1 2

[[2]]
[1] 5

[[3]]
[1] 7 8 9

[[4]]
[1] 11 12 13

[[5]]
[1] 15

Is there any simple way to do this?

K.Hua
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1 Answers1

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An option is to split by creating a grouping variable created by checking the difference of adjacent elements

split(vec, cumsum(c(TRUE, diff(vec) != 1)))
#$`1`
#[1] 1 2

#$`2`
#[1] 5

#$`3`
#[1] 7 8 9

#$`4`
#[1] 11 12 13

#$`5`
#[1] 15
akrun
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    That was exactly what I was looking for ! Thanks ! i will accept the answer when stackoverflow will allow me to – K.Hua Oct 08 '19 at 18:32