const char *hey(const char *arr[])
{}
If I am given the above function, how would I be able to find the length of the array passed in as parameter? Is it strlen? If it is not, could you please explain to me why you can't use strlen here?
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4well, it's an array of pointers. strlen won't work – Jean-François Fabre Oct 12 '19 at 21:23
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@Jean-FrançoisFabre how do you get the length of the array? – hellobyninja Oct 12 '19 at 21:25
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well, that's the catch: you cannot, unless there's a convention with the caller which ends the array with NULL for instance (like execvp does) – Jean-François Fabre Oct 12 '19 at 21:25
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@Jean-FrançoisFabre is there a way to loop through the array? – hellobyninja Oct 12 '19 at 21:29
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With such a declaration you have an **incomplete type**. The C standard allows the use use of array not fully qualified, in that case it is user responsibility to not access memory out of array bounds. In poor words you can't obtain the buffer dimensions... – Frankie_C Oct 12 '19 at 21:29