Powershell Drop the last part of a string with multiple "."

Question

I'm trying to do a regex expression in powershell to get only a specific part of a string. I know a way I can do this without regex but it can definitely be more efficient with. I have a string that looks like this:

Some/Stuff/Here/Then.drop.last

Ideally, I want to write a regex that gets me just:

Then.Drop

score 3 · Accepted Answer · answered Oct 16 '19 at 12:46

PS> 'Some/Stuff/Here/Then.drop.last' -replace '.*/(.+)\..*', '$1'
Then.drop

.*/ greedily matches everything up to the last /
(.+)\. greedily matches everything up to the last literal . and captures everything before that . in the first capture group ($1) - which is your string of interest.
.* matches the remaining part of the string.
Using $1 as the replacement string then replaces the overall match - the entire input string - with what the first capture group matched.

For more information about PowerShell's -replace operator, see this answer.

Powershell Drop the last part of a string with multiple "."

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