How to use zgrep to display all words of a x size from a wordlist?

Question

I want to display all the words from my wordlist who start with a w and are 9 letters long. Yesterday I learnt a bit more on how to use zgrep so I came with :

zgrep '$^w$$^.........$$' a.gz

But this doesn't work and I think it's because I don't know how to do a AND between the two conditions. I found that it should be (?=expr)(?=expr) but I can't figure out how to build my command then

So how can I build my command using the (?=expr) ?

for example if I have a wordlist like this:

Washington
Sausage
Walalalalalaaaa --> shouldn't match
Wwwwwwwww --> should match

Sadly not, I tried to do the things you told me yesterday with escaping the character but I can't figure out how to build this one — J.erome, Oct 17 '19 at 07:13
Will you please show a part of the wordlist and expected matches? `'^w[[:alpha:]]\{8\}$'` should match whole lines that start with `w` and then have 8 letters. — Wiktor Stribiżew, Oct 17 '19 at 07:15

score 1 · Accepted Answer · answered Oct 17 '19 at 07:32

1

You may use

zgrep '^w[[:alpha:]]\{8\}$' a.gz

The POSIX BRE pattern will match a string that

^w - starts with w
[[:alpha:]]\{8\} - then has eight letters
$ - followed with with the end of string marker.

Also, see the 9.3 Basic Regular Expressions.

answered Oct 17 '19 at 07:32

Wiktor Stribiżew

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How to use zgrep to display all words of a x size from a wordlist?

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